(x^2-4x)-(x^2-4x)-12=0

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Solution for (x^2-4x)-(x^2-4x)-12=0 equation: 


Simplifying
(x2 + -4x) + -1(x2 + -4x) + -12 = 0

Reorder the terms:
(-4x + x2) + -1(x2 + -4x) + -12 = 0

Remove parenthesis around (-4x + x2)
-4x + x2 + -1(x2 + -4x) + -12 = 0

Reorder the terms:
-4x + x2 + -1(-4x + x2) + -12 = 0
-4x + x2 + (-4x * -1 + x2 * -1) + -12 = 0
-4x + x2 + (4x + -1x2) + -12 = 0

Reorder the terms:
-12 + -4x + 4x + x2 + -1x2 = 0

Combine like terms: -4x + 4x = 0
-12 + 0 + x2 + -1x2 = 0
-12 + x2 + -1x2 = 0

Combine like terms: x2 + -1x2 = 0
-12 + 0 = 0
-12 = 0

Solving
-12 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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